A rocket is fired at 60 to the horizontal with an initial speed of 200m5 calculate it time of flight and it range on the horizontal plane

See answer below

Explanation:

In order to do this, we just need to apply the expression to determine the time of flight. This is given by:

t = 2 V₀ Sinθ / g   (1)

We have the initial speed which is 200 m/s, the angle of elevation to the horizontalis 60° and the gravity is 9.8 m/s². Replacing this data in the above expression we have:

t = 2 * 200 Sin60° / 9.8

Now that we have the time, we can determine the range or distance in the horizontal plane. This can be calculated using the following expression:

X = V * t   (2)

We already have the time, which is the time of flight, the initial speed using cos 60° (Cause it's horizontal plane), and replacing we have:

X = 200 cos60° * 35.348

X = 100 * 35.348

Hope this helps

c. newton's third law of motion

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