PLEASE HELP A 0.200 plastic ball moves with a velocity of 0.30 m/s . It collides with a second plastic ball of mass 0.1200 K B , which is moving along the same line at a speed of 0.10 m/s * A * f * t * e * r the collision , both balls continue in the same direction and the speed of the 0.1200 K B ball is 0.26 m/s . What is velocity of the first ball after the collision?​

29 m/s.

Explanation:

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Explanation:

the force required to move the cart is divided by three or 33.33 n.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂