A ring of charge is centered at the origin in the vertical direction. The ring has a charge density of λ = 4.48 × 10 − 6 C/m λ=4.48×10−6 C/m and a radius of R = 2.71 cm. R=2.71 cm. Find the total electric field, E , E, of the ring at the point P = ( 1.10 m, 0.00 m). P=(1.10 m, 0.00 m). The Coulomb force constant is k = 1 / ( 4 π ϵ 0 ) = 8.99 × 10 9 N ⋅ m 2 / C 2 .

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small = small current large mag large current

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

e/c, where e is its total energy