Mary pushes a crate by applying force of 18 newtons. unable to push it alone, she gets from her friend, anne. together they apply a force of 43 newtons, and the crate just starts moving. if the coefficient of static friction is 0.11, what is the value of the normal force?

 This problem is relatively simple, in order to solve this problem the only formula you need to know is the formula for friction, which is: 

Ff = UsN 

where Us is the coefficient of static friction and N is the normal force. 

In order to get the crate moving you must first apply enough force to overcome the static friction: 

Fapplied = Ff 

Since Fapplied = 43 Newtons: 

Fapplied = Ff = 43 = UsN 

and it was given that Us = 0.11, so all you have to do is isolate N by dividing both sides by 0.11 

43/0.11 = N = 390.9 which is approximately 391 or C. 3.9x10^2

Idon't know it i just need my points lol