(LT UUU
2. Three point charges are arranged at the corners of a square of side L as
shown in the figure below.
What is the potential at the point A?
(Take V=0 at a great distance).
L
+Q
- 20
L
L
+3Q
У
L​

i'm on my way to history not a mistory.

higher potential

explanation:

because it is in a high speed so it must move into a of high potential

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.