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On a frictionless toy race track, a 0.035 kg toy car moving right at 0.30 collides with another 0.040 kg toy
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car moving left at 0.20 After the collision, the 0.035 kg car moves left at 0.20
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What is the final speed of the 0.040 kg toy car?

Dis your correct answer

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j