A car moving at 10,0 m/s speeds up uniformly to a speed of 30.0 m/s in a time of 5.0 s. What was the car's acceleration?​

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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