An 8 kilogram cannonball is loaded into a 1000 kilogram stationary cannon. When fired horizontally the velocity of the cannonball is 300 meters per second east. Determine the cannon's recoil velocity.

The  recoil velocity of the cannon is 2.38 m/s.

Explanation:

Given;

mass of cannonball, m₁ = 8 kg

mass of stationary cannon, m₂ = 1000 kg

initial velocity of the cannonball, u₁ = 300 m/s

initial velocity of the cannon, u₂ = 0

Let the recoil velocity of the cannon, = v

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

8(300) + 1000(0) = v(8 + 1000)

2400 = v(1008)

v = 2400/1008

v = 2.38 m/s

Therefore, the  recoil velocity of the cannon is 2.38 m/s.

im srry but ur wrong the answer is d a smooth rock, some red dirt, and an empty bird's nest.