The wind chill, which is experienced on a cold, windyday, is related to increased heat transfer from exposedhuman skin to the surrounding atmosphere. Consider alayer of fatty tissue that is 3 mm thick and whose inte-rior surface is maintained at a temperature of 36C. Ona calm day the convection heat transfer coefficient atthe outer surface is 25 W/m2K, but with 30 km/hwinds it reaches 65 W/m2K. In both cases the ambientair temperature is 15C.(a) What is the ratio of the heat loss per unit area fromthe skin for the calm day to that for the windy day

Gas will most likely  fill the container 

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

Idon't get it? what do you mean by playing 17 hours on the wii