A 5 kg block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 11N to the
left. As a result, the block accelerates at 2 m/s2. The coefficient
of kinetic friction between the block and the table is (round
to the nearest hundredth)

Approximately (assuming that , and that the block was initially moving to the left.)

Explanation:

Apply Newton's Second Law to find the net force on this block.

Mass of this block: .

Acceleration of this block: .

.

The block is moving and accelerating towards the left. Hence, friction (which opposes motion) would be towards the right and would be opposite to the direction of the pulling force.

Therefore, the expression for the net force on this object would be:

.

.

Hence:

.

The question states that this table is horizontal. Weight of the block (downwards) and normal force from the table (upwards) are the only two forces on this block in the vertical direction. Hence, the magnitude of the normal force on this block would equal to that of the weight of the block:

.

Calculate the constant of kinetic friction between this block and the table:

.

e/c, where e is its total energy