A 2750 kg helicopter flies horizontally at constant speed. Air resistance creates a 7510 n backward force. What is the magnitude of the lift force created by the propellers

Explanation:

Let lift force F be created by propellers at angle of Ф with the horizontal .

The vertical component of this force will balance the weight of helicopter and horizontal component will balance the air resistance .

F sinФ = mg = 2750 x 9.8 = 26950 N

F cosФ = 7510 N

Squaring and adding ,

F² = 26950² + 7510²

= 726302500 + 56400100

= 782702600

F = 27976.82 N .

pe = weightxheight = 2000x1000=2,000,000joules

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )