Arace car starts from rest and travels east along a straight and level track. for the first 5.0 s of the car's motion, the eastward component of the car's velocity is given by _x(t)=(0.820m/s3)t2.

The solution to your problem is as follows:

a=dv/dt=2*0.82*twhat time velocity is 13.7 solve 13.7=0.82*t^2   t=sqrt(13.7/0.82)  =4.51 sUse the time in the acceleration expression a= 2*0.82*4.51=7.39m/s^2

I hope my answer has come to your help. Thank you for posting your question here in . We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Earthplanet yplanet y5=earth     *many different equationsplanet x1.5=earthplanet x is two times planet yobject 5,2500 mass5,1,3,2,4object 1 is four times obect 4