A particle moving in the xy-plane has velocity v⃗ =(2ti^+(3−t2)j^)m/s, where t is in s. Part A

What is the x component of the particle's acceleration vector at t = 6 s?

Express your answer with the appropriate units.

Part B

What is the y component of the particle's acceleration vector at t = 6 s?

Express your answer with the appropriate units.

A)   2 m/s²

B) -12 m/s²

Explanation:

A)

Applying the definition of instantaneous acceleration as the derivative of the velocity with respect to time, the acceleration vector can be expressed as follows:a = 2i^ + (-2t) j^ m/s²So, the x-component of the acceleration vector is constant, and equal to 2m/s², at any time.When t=6 s, aₓ= 2 m/s²

B)

Applying the definition of instantaneous acceleration as the derivative of the velocity with respect to time, the acceleration vector can be expressed as follows:a = 2i^ + (-2t) j^ m/s²So, when t= 6s, the y component of a is as follows:ay = -2(6s) = -12 m/s²

Ray 2 should cross through the focal point on the right side of the lens.

Mass / weighthope it !