Calculate the force between two objects that have masses of 70 kilograms and 2,000 kilograms separated by a distance of 1 meter.

1. 9.338×10¯⁶ N

2. 5.28×10¯¹⁰ N

Explanation:

1. Determination of the force

Mass of 1st object (M₁) = 70 Kg

Mass of 2nd object (M₂) = 2000 Kg

Distance apart (r) = 1 m

Gravitational constant (G) = 6.67×10¯¹¹ Mm²/Kg²

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 70 × 2000 / 1²

F = 6.67×10¯¹¹ × 70 × 2000 / 1

F = 9.338×10¯⁶ N

2. Determination of the force.

Mass of 1st fruit (M₁) = 0.45 Kg

Mass of 2nd fruit (M₂) = 0.45 Kg

Distance apart (r) = sum of their radius = 0.08 + 0.08 = 0.16 m

Gravitational constant (G) = 6.67×10¯¹¹ Mm²/Kg²

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 0.45 × 0.45 / 0.16²

F = 6.67×10¯¹¹ × 0.45 × 0.45 / 0.0256

F = 5.28×10¯¹⁰ N

ice to water 1 water to vapour 2 latent heat

d. air pressure decreases as altitude increases.