Using a digital voltmeter, you measure the voltage of a 9 Volt battery to be 23.1244 Volts. Discuss both the accuracy and precision of this measurement

Pe = 1/2k(x)^2  and .05n/m = .05x10^-9m = x 

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.