BRAINLIEST WILL BE GIVEN After communicating the information you requested above, he pushes the sled a total distance of 50 m and exerts a horizontal force of 800 N. During the sled push he pushes the sled 25 m, turns around and pushes it 25 m back to where he started. He argues that the work done is 40000 J, but you say the total work is actually 0 J. Why are you correct and he is wrong?

W=F*D

40,000=800*50

With this you are wrong and he is right because work is not like displacement where if you go 10 ft to the right then 10 ft to the left you have traveled gone 0 ft from original spot. because your distance was 50 m and you exerted 800 N you multiply that together and come out with 40,000 so HE IS RIGHT YOU ARE WRONG.

PLZ mark as brainliest

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.