Until it was recently discontinued , the fastest jet plane in the skies was the Lockheed SR-71 Blackbird . However , this plane did not reach its high speeds through large acceleration . The plane had a mass of 7.7*10^ 4 kg and was driven by an estimated unbalanced force of about 7.23 * 10 ^ 5 * N What was the acceleration of the Lockheed SR- 71?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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Attach the free body diagram and i will you answer the question.! : d