3. A dentist uses a small concave mirror of focal length 3.0 cm and holds it at a distance of 2 cm from the tooth. What is the magnification of the image?

Given :-

Focal length = -3 cm

Object Distance = -2 cm

To Find :-

Magnification

Solution :-

As we know that

1/f = 1/v + 1/u

F is the Focal length

V is the Image distance

U is the object Distance

1/-3 = 1/v + 1/-2

-1/3 = 1/v - 1/2

1/v = -1/3 + 1/2

1/v = -2 + 3/6

1/v = ⅙

v = 6 × 1

v = 6 cm

Hence :-

Image distance = 6 cm

Now,

m = -v/u

m = -6/-2

m = 6/2

m = 3

Hence :-

Magnification = 3

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