Problem 5. A bullet leaves a rifle with a velocity of 452 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.93 m. Determine the acceleration of the bullet.

1.1 x 10⁵m/s²

Explanation:

Given parameters:

Velocity  = 452m/s

distance  = 0.93m

Unknown:

Acceleration of the bullet  = ?

Solution:

To solve this problem, we use one of the kinematics equation which is given below:

           V² = U²  + 2aS

V is the final velocity

U is the initial velocity  = 0m/s

a is the unknown acceleration

S is the distance traveled  

 So;

          452²   = 0²  + (2 x a x 0.93)

          204304  = 1.86a

               a  = 1.1 x 10⁵m/s²

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