A satellite is in orbit 36000km above the surface of the earth. Its angular velocity is 7.27*10^-5 rad/s. What is the velocity of the satellite? (The radius of the earth is 6400km.)

v = 3.08 km/s

Explanation:

Given that,

The angular velocity of the satellite =

A satellite is in orbit 36000km above the surface of the earth.

The radius of the earth is 6400 km

Let v is the velocity of the satellite. It can be calculated as :

So, the velocity of the satellite is 3.08 km/s.

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000