Physics, 29.01.2021 16:40 angie249

Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be added to the gas in the form of heat by applying a flame to the outside of the container. Conversely, energy can also be removed from the gas in the form of heat by immersing the container in ice water. Energy can be added to the system in the form of work by pushing the piston in, thereby compressing the gas. Conversely, if the gas pushes the piston out, thereby pushing some atmosphere aside, the internal energy of the gas is reduced by the amount of work done.

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Answer from: jbot9050

Complete Question

Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be added to the gas in the form of heat by applying a flame to the outside of the container. Conversely, energy can also be removed from the gas in the form of heat by immersing the container in ice water. Energy can be added to the system in the form of work by pushing the piston in, thereby compressing the gas. Conversely, if the gas pushes the piston out, thereby pushing some atmosphere aside, the internal energy of the gas is reduced by the amount of work done.

pV=nRT

so the absolute temperature T is directly proportional to the product of the absolute pressure p and the volume V,Here n denotes the amount of gas moles,which is a constant because the gas is confined and R is the universal constant

What is the $\triangle U$ as the system of ideal gas goes from point A to point B on the graph recall u is proportional to T

$\triangle T=0$

$\triangle V=0$

The gas A and B have same internal energy

Explanation:

From the question we are told that

$Pa=u atm\\Va=1m^3\\Pb=1 atm\\Vb=4m^3$

Generally the equation of temperature is mathematically given as

$Ta=\frac{Pv}{nR}$

$Ta=\frac{u*1}{nR}$

And

$Tb=\frac{PbVb}{nR}$

$Tb=\frac{u*1}{nR}$

Generally the change in temperature $\triangle T$ is mathematically given as

$\triangle T=Tb-Ta=Tb=\frac{u*1}{nR}-\frac{u*1}{nR}$

$\triangle T=0$

Generally the change in internal energy $\triangle V$

$\triangle V=nC_v \triangle T\\$

$\triangle V=0$

Therefore with

$\triangle T=0$

$\triangle v=0$

The gas A and B have same internal energy

Answer from: Quest

the answer would most likely be c, because if it's a comical piece of information, it may likely not be true, if it's a site that allows anybody to edit the content, it could mean a five year old is typing the info, and if it's a tv show produced by a celeb, it may have a biased opinion.

Answer from: Quest

Answer

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

explanation

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

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