A 56-kg skater initially at rest throws a 5.0-kg medicine ball horizontally to the left. Suppose the ball is accelerated through a distance of 1.0 m before leaving the skater's hand at a speed of 7.0 m/s. Assume the skater and the ball to be point-like and the surface to be frictionless and ignore air resistance. Use a vertical y-axis with the positive direction pointing up and a horizontal x-axis with the positive direction pointing to the right. What will happen to the skater and the ball after the ball is thrown

towards right

towards left

Explanation:

= Mass of skater = 56 kg

= Mass of ball = 5 kg

v = Final velocity of ball = 7 m/s

u = Initial velocity of ball = 0

s = Distance the ball moved in the hand of the skater = 1 m

Moving left is considered and moving right is considered positive.

From kinematic equations of motion we have

So, the ball will move towards right with a magnitude of acceleration .

The force on the ball will be

The force on the ball is

The reaction force on the skater will be equal to the force on the ball but will have opposite direction.

So, the skater will move towards left with a magnitude of acceleration

the answer is a 3.8cm

explanation: