3. A 200-g ball falls vertically downward, hitting the floor with a speed of 2.5 m/s and rebounding upward with a speed of 2.0 m/s. a. Determine the change in momentum of the ball.. b. If the ball is in contact with the floor for 0.02 ms (milliseconds), what is the average force applied to the ball

Explanation:

A 200-g ball falls vertically downward, hitting the floor with a speed of 2.5 m/s and rebounding upward with a speed of 2.0 m/s. a. Determine the change in momentum of the ball.. b. If the ball is in contact with the floor for 0.02 ms (milliseconds), what is the average force applied to the ball

Given data

mass= 200g= 0.2kg

initial velocity= 2.5m/s

final velocity= 2m/s

time= 0.02ms

time= 0.00002 seconds

ΔP= mΔv

ΔP= 0.2*2.5-2

ΔP= 0.2*0.5

ΔP=0.1kgm/s

F= mv/t

F=0.1/0.00002

F=5000N

because growing process had stoped after 4-5 year

80cm/s.

24cm/s.

53.3cm/s.