A hockey puck slides to a stop on ice. The coefficient of friction between the puck and the ice is 0.026. What is the puck’s acceleration?

Explanation:

The puck slides on the ice . Coefficient of sliding friction μ = .026

Limiting frictional force = μ R

R is reaction force of the surface .

R = mg

Friction force = μ mg

deceleration = μ mg / m

= μ g

= .026 x 9.8 = .2548

= 0.26 m /s².

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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