A force of 5.0 moves a 6.0 kg object along a rough floor at a constant speed of 2.5 m/s. What power is being used? What force of friction is acting on the object?

Complete Question:

A force of 5.0 N moves a 6.0 kg object along a rough floor at a constant speed of 2.5 m/s.

(a) How much work is done in 25 s?

(b) What power is being used?

(c) What force of friction is acting on the object?

a. Workdone = 312.5 Joules.

b. Power = 12.5 Watts.

c. Force of friction = 5 Newton.

Explanation:

Given the following data;

Force = 5N

Speed = 2.5m/s

Mass = 6kg

Time = 25 secs

a. To find the work done.

We would first solve for the distance covered by the object.

Distance = speed * time

Distance = 2.5 * 25

Distance = 62.5 meters.

Workdone = force * distance

Workdone = 5 * 62.5

Workdone = 312.5 Joules.

b. To find the amount of power being used.

Power = workdone/time

Power = 312.5/25

Power = 12.5 Watts.

c. To find the force of friction is acting on the object.

Since we know that there is no net force acting on the body. Therefore, the force of friction is equal to 5 Newton.

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