The center of mass of a cow and the center of mass of a tractor are 208 meters apart. The magnitude of the gravitational force of attraction between these two objects is calculated to be 1.8 × 10-9 newtons. What would the magnitude of the gravitational force of attraction be between these two objects if they were 416 meters apart?
A.
1.62 × 10-9 newtons
B.
3.6 × 10-10 newtons
C.
9 × 10-10 newtons
D.
4.5 × 10-10 newtons

Explanation:

The gravitational force between two masses is inversely proportional to the square of the distance between them such that,

.....(1)

We have,

r₁ = 208 m, , r₂ = 416 m, F₂ = ?

Put all the values in relation (1) such that,

So, the required force is . Hence, the correct option is (d).

b

explanation:

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