A potato gun is fired horizontally from a height of 1.5 meters with the potato launched at 25 m/s What is the time of flight of the potato?

0.55 s

Explanation:

From the question given above, the following data were obtained:

Height (h) = 1.5 m

Horizontal velocity (v) = 25 m/s

Time of flight (t) =?

The time of flight of the potato talks about the total time spent by the potato in the air i.e the time taken for the potato to get to the ground..

Thus, we can obtain the time of flight of the potato as illustrated below:

Height (h) = 1.5 m

Acceleration due to gravity (g) = 9.8 m/s²

Time of flight (t) =?

H = ½gt²

1.5 = ½ × 9.8 × t²

1.5 = 4.9 × t²

Divide both side by 4.9

t² = 1.5 / 4.9

Take the square root of both side

t = √(1.5 / 4.9)

t = 0.55 s

Thus, the time of flight is 0.55 s

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.