A tourist drops (from rest) a ping pong ball from the top of the tower, which has a height of 174 meters. Assuming no air resistance, how long does it take for the ping pong ball to hit the ground

Given :

A tourist drops (from rest) a ping pong ball from the top of the tower, which has a height of 174 meters.

To Find :

How long does it take for the ping pong ball to hit the ground ?

Solution :

We know, equation of motion of object doing free fall is :

          ....1)

Here, g = 9.8 m/s² ( acceleration due to gravity )

Also, u = 0 m/s ( its free fall )

Putting these values in equation 1), we get :

Therefore, ball will take 5.96 s to hit the ground.

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary