A 3.6kg cat is laying on a tree branch, 3 meters above the ground. What is the cat’s potential energy?

E = 105.84  J

Explanation:

Given that,

Mass of cat, m = 3.6 kg

It is laying 3 meters above the ground.

We need to find the cat's potential energy. The formula for the potential energy of an object is given by :

E = mgh

Substituting all the values,

E = 3.6 kg × 9.8 m/s²×3 m

E = 105.84  J

So, the cat's potential energy is 105.84  J.

c. magnitude and direction

i believe the answer is electric potential.

explanation: