While driving his sports car at 20.00 m/s down a four lane highway, a man comes up behind a very slow school bus. The man is in a hurry so he
decides to pass the bus. If the man's car can accelerate at 6.00 m/s^2,
how long will it take for him to reach a speed of 35.00 m/s in order to pass
the bus? Round to the nearest hundredth. (2 decimal places) Type the
number only.

2.50 s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 20 m/s

Acceleration (a) = 6 m/s²

Final velocity (v) = 35 m/s

Time (t) =?

Thus, we can obtain the time taken for the man to reach a speed of 35 m/s as follow:

v = u + at

35 = 20 + 6t

Collect like terms

35 – 20 = 6t

15 = 6t

Divide both side by 6

t = 15/6

t = 2.50 s

Thus, it will take the man 2.50 s to reach a speed of 35 m/s.

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