When a tuning fork of frequency 201 Hz vi-brates beside a piano string, beats are heard. The string is tightened slightly and the beatsgo away. What was the original frequency of thestring

the original frequency of the string is less than 201 Hz.

Explanation:

Given;

frequency of the tuning fork, F = 201 Hz

Decrease in length of the string by tightening it slightly increases the frequency of the string, thus the original frequency of the string should be less than 201 Hz to create a beat frequency with the tuning fork.

Once the string is tightened slightly, its frequency increases to be equal to 201 Hz, which cancels the beats heard.

Therefore, the original frequency of the string is less than 201 Hz.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

vapour or gas assuming atmospheriv pressure