If the coefficient of static friction between the coffee cup and the roof of the car is 0.20, what is the maximum acceleration the car can have without causing the cup to slide

a = 1.962 m/s²

Explanation:

The frictional force applied on the car can be given by the following formula:

where,

f = frictional force = ma (according to Newton's Second Law)

μ = coefficient of friction = 0.2

R = Normal Reaction = Weight of car = mg

Therefore, equation becomes:

where,

a = maximum acceleration = ?

μ = coefficient of friction = 0.2

g = acceleration due to gravity = 9.81 m/s²

Therefore,

a = 1.962 m/s²

resonant frequency

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y