A ball of mass 0.3kg, moving at a velocity of 20m/s is suddenly hit by a force of 5N for a time of 0.03 sec. Find its new velocity of motion

F * t = m * Δv

F * t = m * (v2 - v1) where v2 is the new velocity and v1 is the current velocity

m * (v2 - v1) = (F * t)

Plugging in the values,

0.3kg * v2 - 0.3kg * 20 m/s = 5 * 0.03 s

0.3 * v2 - 6 = 0.15

0.3 * v2 = 0.15 + 6

v2 = 6.15 / 0.3

v2 = 20.5 m/s

The new velocity of motion is 20.5 m/s.

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see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west