A student pushes a 12 N book to the right with a force of 10 N. The book experiences a frictional force of 3 N. The free-body force diagram below
represents the forces acting on the book. What is the magnitude of the net force
acting on the book?
12 N
3N ION
I2N
ON
11 N
13 N
37 N

the magnitude it is 22.85 you get your magnitude by squaring up the force and looking for the square root you'll you will be having our 22.85 so that's the magnitude when Magnesium in the square root of all the squares of the first is the sum of the squares of the forces after the thing is on what the squares of the first is there a new look for his grades then to look for the direction then that means it will have to be I can't really say shower but but the direction is not it's not like it's not specific so that's why I got just before now so for me I'll see the direction for now I can't get it I'll

Explanation:

d they tend to lose electrons and become cations.

explanation:

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j