An energy source forces a constant current of 2A to flow through a light bulbfilament for twenty seconds. If 4.6 kJ is given off in the form of light and heatenergy, calculate the voltage drop across the bulb.

The voltage drop across the bulb is 115 V

Explanation:

The voltage drop equation is given by:

Where:

ΔW is the total work done (4.6kJ)

Δq is the total charge

We need to use the definition of electric current to find Δq

Where:

I is the current (2 A)

Δt is the time (20 s)

Then, we can put this value of charge in the voltage equation.

Therefore, the voltage drop across the bulb is 115 V.

I hope it helps you!

the answer would be 32*f