In a hydraulic lift, the radius of the small and large pistons are 2.50cm and 10.0cm respectively. A vehicle weighing 12.0kN is to be
lifted by the large piston. Calculate
a) the force that must be applied to the small piston
b) the distance that the small piston has to be pushed down to raise the vehicle a diatance of 2.00cm

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

iron would move it is magnetic there is a mag field around the current in the wire

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y