What is the net force acting on a box that is being pulled to the right with a 50 N force and to the left with a 10 N force? to the

We have that for the Question "What is the net force acting on a box that is being pulled to the right with a 50 N force and to the left with a 10 N force? to the " it can be said that The appropriate statement is

From the question we are told

What is the net force acting on a box that is being pulled to the right with a 50 N force and to the left with a 10 N force? to the

Generally the equation for the Net force  is mathematically given as

Fn=F_2-F_1

Therefore

Fn=F_2-F_1

Fn=50-10

Fn=40N

Therefore

The appropriate statement is

The net Force is 40N to the right

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Explanation:

A box that is pulled by 2 forces:

50N - 10N = 40N.

Since the force acting towards the right is stronger, there is a net force of 40N to the right and the box will move towards the right (if it has low static friction coefficient)

The answer is 40N to the right.

trig 15.3 cos

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day