The graph above shows the position and time calculate the velocity of the particle from T=0s to T=4s? 0.75m/s
0.5m/s
2m/s
1.33m/sm/s

The velocity of the particle from T = 0 s to T = 4 s is;

0.5 m/s

Explanation:

The given parameters from the graph are;

The initial displacement (covered) at time, t₁ = 0 s is x₁ = 1 m

The displacement covered at time, t₂ = 4 s is x₂ = 3 m

The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;

The velocity of the particle from t = 0 s to t  = 4 s = 1/2 m/s = 0.5 m/s.

we need to know the time interval during which the force acts. impulse of force = momentum change

i think the answer is a, hope this : )