A tennis ball is thrown upwards from the edge of a cliff with a speed of 10\,\dfrac{\text m}{\text s}10 s m 10, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. It lands on the ground below the cliff 3.03.03, point, 0 seconds later. We can ignore air resistance. What is the displacement of the tennis ball? Answer using a coordinate system where upward is positive. Round the answer to two significant digits.

5.1m

Explanation:

Given the following parameters

Speed v = 10m/s

Time = 3.0s

Required

Displacement of the tennis ball

Using the equation of motion

v² =u²-2gh (g i s negative due to upward motion of the ball)

Substitute the given values into the expression above;

0² = 10²-2(9.8)h

0 = 100-19.6h

19.6h = 100

h = 100/19.6

h= 5.1m

Hence the displacement of the ball is 5.1m

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hope this !

this could be newton#'s law of cooling. the cooling curve is exponential