The time of flight for an object thrown from the rooftop of a tall building is 6.2 seconds. In terms of the initial launch velocity v, and the angle of launch o, what equation gives you the maximum displacement of the object?

B . x= v*cos ∅* 6.2

Explanation:

Time of flight of a projectile motion is the time taken by the object to reach the surface from when it was projected.

In this case ;

Initial launch velocity = v

Angle of launch is =∅

Time of flight = 6.2 seconds

The formula for time of flight is;

T= 2*v*sin∅  / g

At time t the displacement components for x and y are;

x= v* t * cos ∅  i

and

y =u* t * sin ∅ - 1/2 g*t² ii

Taking equation i for displacement of the object in the x component

x = v* t* cos ∅

x = v * cos ∅ * 6.2

x = 6.2* v * cos ∅

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the inner core.

good luck: )

klicker