Determine the small gravitational force F which the copper sphere exerts on the steel sphere. Both spheres are homogeneous, and the value of r is 65 mm. Express your result as a vector.

acting along the line joining both the sphere and always attractive in nature.

Explanation:

The given radius of both the sphere, r= 65 mm = 0.065 m

So, the volume of the spheres,

The density of steel,

and the density of copper,

Let M be the mass of the copper ball and m  is the mass of the steel ball.

So, kg

kg

The gravitational force, F, between the two objects having masses M and m and separated by distance d is

Where is the universal gravitational constant.

When both the sphere touches each other, d = 2r= 2 x 0.065 = 0.13 m

Hence, the gravitational force between both the sphere,

The nature of gravitational force is always attractive and acting along the line joining the center of both the sphere.

change tension

the skeletons of most mammals reach a certain size and then stop growing. however, many animals, including some mammals, keep growing throughout their lives. kangaroos, for example, just keep growing and growing until they die. also, the longer an animal lives the greater the chance it might catch some deadly disease.