A 747 requires a takeoff speed of 270 meters per second if it is to get off the ground. Calculate the acceleration required for the 747 that begins from rest
to takeoff on a 1000 meter long runway.

a = 36.45[m/s²]

Explanation:

We can calculate the acceleration value by means of the following expression of kinematics.

where:

vf = final velocity = 270 [m/s]

Vo = initial velocity = 0 (begins from rest)

a = acceleration [m/s]²

x = distance required by the plane = 1000 [m]

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)