a 2kg box frictionless ramp angle 60 degrees top of ramp is 30 m how long will it take to reach the ground

2.66secs

Explanation:

To get the time it will take to reach the ground, we will use the equation of motion;

S = ut + 1/2at²

S is the distance

u is the initial velocity

g is the acceleration due to gravity

Given

S = 30m

u = 0m/s

Let's get the acceleration

According to newton's second law;

Get the required time:

Recall that: S = ut + 1/2at²

Substitute the given parameters and find t

30 = 0(t) + 1/2(8.49)t²

30 = 4.24t²

t² = 30/4.24

t² = 7.08

t = √7.08

t = 2.66secs

Hence it take the box 2.66seconds to reach the ground

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr