What is the efficiency of a machine that lifts a load of 12.0 kg a vertical distance of 5.00 m in 30.0 s after being supplied with 70.0 W of power? Explain the steps you take to get the answer.

Efficency = 28%

Explanation:

We have the load has a weight of:

Work in physics is defined as the product of force (weight) by distance.

where:

W = work [J]

w = weight = 117.72[N]

d = distance = 5 [m]

Now power is defined as the relationship of work at a certain time.

where:

P = power [W]

W = work = 588.6[J]

t = time = 30[s]

Now the efficiency of a machine is defined as the power output over the power input to the machine. The power input should always be greater than the power output.

the assestment will probley apele with cause and effect

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.