A proton with an initial speed of 600,000 m/s is brought to rest by an electric field.1. What was the potential difference that stopped the proton? 2. What was the initial kinetic energy of the proton, in electron volts?

(1) the potential difference that stopped the proton is 1878.75 V

(2) the initial kinetic energy of the proton is 1878.75 eV

Explanation:

Given;

initial speed of the proton, v = 600,000 m/s

mass of proton, m = 1.67 x 10⁻²⁷ kg

(1) The work done in bringing the proton to rest is given as;

Apply work energy theorem;

where;

V is the potential difference

(2) the initial kinetic energy of the proton, in electron volts;

i would say the answer is food.

hope this !

option number c is the right answer.