A student heated 50mL of water from zero degree Celsius to 60 degree Celsius. How much energy did she use to heat the water? Remember cal = m x delta T

Q = 12.5 kJ

Explanation:

Given that,

Mass of water, m = 50 mL = 0.05 kg

The temperature changes from 0 degree Celsius to 60 degree Celsius.

We need to find how much energy she use to heat the water. The energy required to heat the water is given by :

Where c is specific heat of water, c = 4186 J/kgºC

or

Q = 12.5 kJ

So, the energy used to heat th water is 12.5 kJ.

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is