A softball pitcher rotates a 0.250 kg ball around a vertical circular path of radius 0.5 m before releasing it. The pitcher exerts a 33.0 N force directed parallel to the motion of the ball around the complete circular path. The speed of the ball at the top of the circle is 13.0 m/s. If the ball is released at the bottom of the circle, what is its speed upon release

The value is  

Explanation:

From the question we are told that

   The  mass of the ball is

    The radius of the circle is  

    The force exerted is  

    The  speed of the ball on top of the circle is  

Gnerally from the law of energy conservation we have that

Here PE  is the potential energy of the pitcher which is mathematically represented as

=>    

=>  

And  W  is the workdone by the force applied which is mathematically represented as

=>    

=>    

And   is the change in kinetic energy which is mathematically represented as

=>    

=>    

=>    

So

=>    

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards