in a hydraulic press, a force of 200N is applied to a master piston of area 25cm² if the press is designed to produce a force of 5000N, determine the radius of the slave piston

The radius of the slave piston = 14.10 cm

Explanation:

The formula to apply here is that for pressure where ;

Pressure = Force / Area

F₁ /A₁ =F₂/A₂    where ; F₁=200 N  , A₁= 25 cm² , F₂ =5000 N ,A₂ =?

Apply values in the equation as ;

200/ 25 = 5000/ A₂

A₂ = 625 cm²

Formula for area is ;

A = πr²  

625 = π * r²

625/π = r²

√625/π =r

14.10 cm = r

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

i don't understand. explain it clearly