A ball of mass 0.190 kg has a velocity of 1.50 i m/s; a ball of mass 0.305 kg has a velocity of -0.401 i m/s. They meet in a head-on elastic collision. (a) Find their velocities after the collision.

Explanation:

According to law of conservation of momentum, the momentum of the object before collision is equal to that of the object after collision. Using the formula

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses of the object

u1 and u2 are the respective initial velocities

v is the final velocity

Given

m1 = 0.190kg

u1 = 1.5m/s

m2 = 0.305kg

u2 = -0.401m/s

Substitute

0.19(1.5)+(0.305)(-0.401) = (0.19+0.305)v

0.285 - 0.122305 = 0.495v

0.162695 = 0.495v

v = 0.162695 /0.495

v = 0.329m/s

Hence their velocities after collision is 0.329m/s in the positive x direction

it breaks and dirupture other materials and other sencews from the bottom

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force