An irrigation system supplies water at a pressure of 0.5 MPa and flow rate of 5,000 liter per hour. If both the pump and motor are 100% efficient, what is the current required of a 220 volt service. Give your answer as a bare number in amps, with no units attached.

3.16 A

Explanation:

The irrigation system has a motor which is used to drive the pump. The efficiency of the system is the ratio of the power output to power input. It is given as:

Efficiency = Power output / Power input

Given that efficiency = 100%  = 1, flow rate = 5000 liter / hour = 0.00139 m³/s, pressure = 0.5 MPa = 0.5 * 10⁶ Pa, voltage = 220 V.

Power output = supply of the pump = flow rate * pressure

Power output = 695 W

Efficiency = Power output / Power input

1 = 695 / power input

Power input = 695 / 1

Power input = 695 W

Also, Power input = input of motor = voltage * current

Power input = voltage * current

695 = 220 * current

current = 695 / 220

current = 3.16 A

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: